0=-16x^2-32x+110

Solution for 0=-16x^2-32x+110 equation:

0=-16x^2-32x+110

We move all terms to the left:

0-(-16x^2-32x+110)=0

We add all the numbers together, and all the variables

-(-16x^2-32x+110)=0

We get rid of parentheses

16x^2+32x-110=0

a = 16; b = 32; c = -110;
Δ = b2-4ac
Δ = 322-4·16·(-110)
Δ = 8064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8064}=\sqrt{576*14}=\sqrt{576}*\sqrt{14}=24\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-24\sqrt{14}}{2*16}=\frac{-32-24\sqrt{14}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+24\sqrt{14}}{2*16}=\frac{-32+24\sqrt{14}}{32}
$